Re: [SQL] Special grouping on sorted data.

Craig Ringer wrote:
>>
>> b | n | stamp
>> ----------------------------------------
>> A | 1 | 2008-09-20 06:07:47.981445 [1]
>> A | 1 | 2008-09-20 06:08:13.294306 [1]
>> A | 1 | 2008-09-20 06:12:02.046596 [1]
>> A | 2 | 2008-09-20 06:12:26.267786 [2]
>> A | 2 | 2008-09-20 06:12:47.750429 [2]
>> A | 1 | 2008-09-20 06:13:12.152512 [3]
>> A | 2 | 2008-09-20 06:13:39.052528 [4]
>> A | 2 | 2008-09-20 06:14:12.875389 [4]
>>
>
> I'd be tempted to use a set-returning PL/PgSQL function to process an
> input set ordered by stamp and return a result whenever the (b,n) pair
> changed. I'm sure there's a cleverer set-oriented approach, but it's
> eluding me at present.
>
> You need a way to express the notion of "contiguous runs of (b,n)"
> which doesn't really exist in (set-oriented) SQL.

The numbers you have next to each row is exactly what I'm looking for.
You mention PL/PgSQL, I'm familiar with creating triggered procedures so
I'll look into that

> I suspect that Crystal Reports may be pulling the whole data set from
> PostgreSQL then doing its processing client-side.
Crystal report is running a simple pass through query that I wrote,
select b.n.stamp from table where stamp .... order by stamp
Then I use its grouping features, I group by b, then n but when I group
by n I don't specify ascending or descending order but "in original order"
And it ends up doing what I'm looking for.

I which distinct on was more flexible, it's not happy when the order by
set is different than the distinct on set.

I would like to be able to write select distinct on (b,n) b,n,stamp from
table where ... order by stamp;

Nicolas

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