> Double holds 15 places which is the highest value of precision it can
> maintain before rounding occurs.
>
> Is is limit less no, but what is?
>
> Practically speaking taking a vale 0.000,000,000,000,001 aka
> 1 trillionth of anything,
But remember that if you add this value onto a large number and then
take off the large number the result will be zero.
(0.000,000,000,01 + 1,000,000) - 1,000,000 ==> 0
0.000,000,000,01 + (1,000,000 - 1,000,000) ==> 0.000,000,000,01
In general, operations on floating point numbers will increase their
errors.
> i view the problem solved for 98% of problems.
Floating point math is good for most problems, hence why most languages
expose the abstraction.
Sam
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